-16x^2-8x+20=x

Solution for -16x^2-8x+20=x equation:

-16x^2-8x+20=x

We move all terms to the left:

-16x^2-8x+20-(x)=0

We add all the numbers together, and all the variables

-16x^2-9x+20=0

a = -16; b = -9; c = +20;
Δ = b2-4ac
Δ = -92-4·(-16)·20
Δ = 1361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{1361}}{2*-16}=\frac{9-\sqrt{1361}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{1361}}{2*-16}=\frac{9+\sqrt{1361}}{-32}
$